260723_LP5_Theaterplatz_Aachen_Fugenplan_M250_2020_27_AP_L6.pdf

[Seite 1]

1827 1+250.00

-

8 n

2

3 0 8 r

1+245.00 1 9 1 o

9 6 2

1 h Tk 1 B

S m 1

16

1+ 6 0 1+240.00 km = 1+203.198 2 0 .5 7 0 m 2 .13 9 % 2 .3 7 0 m 2 2 3 .7 6 8 1 9 0 6 1 2 0 4 hTS = 162.810 m 1 H = 0 m T = 0.000 m4 5 f = 0.0001 m 1 1+235.00 6 3

1 1 6 0 1 3

2.139 % 0.583 % km = 1+175.7661 1 6 0 9 9 km = 1+150.761 km = 1+125.761 km = 1+116.706 1 km = 1+103.861 20.570 m 27.437 m hTS = 162 1 .970 m 1 1 5 hTS = 162.900 m hTS = 162.950 m hTS = 162.950 m hTS = 162.930 m H = 0 m H = 0 m H = 0 m H = 0 m H = 0 m 1+230.00 T = 0.000 m T = 0.000 m T = 0.000 m T = 0.000 m T = 0.000 m 8 s e 8 2 f = 0.000 m f = 0.000 m f = 0.000 m f = 0.000 m f = 0.000 m 5 9 n g a s

7 1 or

8 1 0.583 % 0.280 % 0.280 % 0.200 % 0.200 % 0.000 % 0.000 % 0.156 % 0.156 % 0.722 % B 0 R R 1 R = + = R 2 = ∞ 2 2 = 0 0 2 1 . + 1 0 0 0 2 0 15. 1 0 1 + 2 0 + 1 1 0. 2 + 0 0 2 2 1 4 7 . . 5 4 3 6 7 9 1 + 2 0 5 1 . 0 0 +22 R = 5 1 0 .0 R 0 = 1 + % 0 0 ,2 1 2 7 0 . 5 8. 0 0 0 .0 0 2 + 1 5 .7 1 = R 8 9 1.3 0 2 + 1 ∞ = R 2 -Q 0 0 .5 9 1+ 1 1 0 0 .0 9 1+ 1 0 0 .5 8 1+ 1 0 0 .0 8 1+ 1 27.437 m m 0 7 9 .2 6 1= H ,16 7 .5 7 1+ 1 P H 0 0 .5 7 1+ 1 25.000 1 m a 0 0 .0 7 1+ 1 0 0 .5 6 1+ 1 3 0 0 .0 6 1+ 1 5 0 0 .5 5 1+ 1 25.000 m m 0 0 9 .2 6 1= H ,16 7 .0 5 1+ 1 P T 0 0 .0 5 1+ 1 25.000 m 0 0 .5 4 1+ 1 7 0 0 .0 4 1+ 1 0 0 .5 3 1+ 1 25.000 0 0 .0 3 1+ 1 m 9.055 m 0 0 .5 2 1+ 1 9 0 0 .0 2 1+ 1 % 0 8 / % 0 0 ,2 11 9.0 3 -Q 55 0 0 .5 11+ 1 m 12 e g a ssa P .845 m 0 0 .0 11+ 1 12.84 1 5 3 0 0 .5 0 1+ 1 m ∞ = R 5 6 8 .3 0 1+ 1 0 1 = R 23.554 m 1 +1 0 0. 0 0 15 1+095.00 1 1 1 234.5 0 5 .7 4 2 2 m % f 3 T = 0 h H . 0 = T 3 0 . S 1 . 7 = k 0 0 0 5 m 0 . = 0 9 0 0 m 0 = 1 0 m % m 6 1 2 m + .7 0 6 8 0 0 .3 m 07 h k T m S H = = = 1 1 5 + 6 0 0 2 0 4 . 9 9 m 9 . 0 9 9 m 7 h k T m S H = = = 1 1 5 + 6 0 0 3 0 3 . 4 4 m 0 .9 0 9 m 8 1 8 2 6 k m = 0 + 9 8 7. 0 3 5 h T S = 1 6 5. 2 4 0 m % 5 8 5 .2 m 9 4 3 .7 h k T m S H = = = 1 1 9 + 6 0 0 4 0 0 . 8 4 m 0 .9 0 9 m 8 2 7

X ,1 X 6

T = 4.936 m T = 4.833 m T = 10.401 m 1 f = 0.024 m f = 0.023 m f = 0.060 m 7 Neubau Schacht 01 % 0 0 ,2 % 0 2 ,2 beton beton beton 3,67 7 6 ,3 19 % 0 0 ,2 % 0 0 ,2 Neubau Schacht 02 Neubau Schacht 03 1+09 X 0.00 R T R P = 1 + = 0 G 8 1 0 0 1 . 3 1 2 0 + 7 0 , H 8 = 5 1 6 . 2 0 1 . 7 + 0 6 0 0 1 m + 9 0 8 0 0. 0 . 0 22 % 0 8 ,2 % 0 0 ,1 1 3 1 + 0 7 5. 0 0 2 1 = R 2 6 8 .3 7 0 + 1 ∞ = R 0 0 .0 7 0 + 1 0 0 .5 6 0 + 1 1 0 0 .0 6 0 + 1 X 0 0 .5 5 0 + 1 m 3 5 9 .2 6 1= H ,4 3 9 .4 5 0 + 1 E A 3 0 0 .7 .3 5 3 1 9 0 % m 0 0 .0 5 0 + 1 2 14 .7 . 3 9 3 9 9 % X m ei m 5 2 1.3 6 1= H ,16 0 .5 4 0 + 1 A A ng 0 0 .5 4 0 + 1 ang eingang5 0 0 .0 4 0 + 1 m 8 6 2 .3 6 1= H ,13 8 .9 3 0 + 1 E A eee 2 1 iii % 0 6 ,1 % 0 0 ,1 nnn 4 .7 ggg . aaa 3 9 nnn 3 9 ggg 9 % m 0 0 .5 3 0 + 1 4 -Q 4 3 . 0 6 . 6 0 7 0 0 % m m 6 2 6 .3 6 1= H ,5 6 1.0 3 0 + 1 A A 0 0 .0 3 0 + 1 7 0 0 .5 2 0 + 1 k m = 0 + 9 9 4. 3 8 4 h T S = 1 6 5. 0 5 0 m H = 0 m T = 0. 0 0 0 m pod 0 0 .0 2 0 + 1 f = 0. 0 e 0 0 m st p % o 5 8 5 .2 d % 5 5 3 . e 2 st m 9 4 3 .7 m 4 16 .0 1 m 5 13 .4 6 1= H ,8 9 3 .5 10 + 1 E A 0 0 .5 10 + 1 9 ∞ = R % 0 1,1 % 0 7 ,0 4 8 4 .0 0 0 + 1 4 = R 0 0 .0 10 + 1 4 3 6 . 0 6 8 . 6 2 0 7 . 0 4 0 9 % 9 m + 0 0 .5 0 0 + 1 0 m 1 5 6 4 7 e e 0 i 2 i . n 1 e n 5 . f i 0 . f ∞ 5n 4 3 a 8 a f . h 6 h 6 5 a 9 r r h 1 = 1 5 = t t + r = 4 t 0 H R % R 0 0 .0 0 0 m + 1 , e 7 in 9 fa 5 h . r 4 t 99 ∞ +0 = A R A 1,00 Neubau Schacht 05 13

B e et g041

Bestand Schacht halten

n e b 2,4% 2,0% 2,0% Q-1 1

6 1

7 4,60 % 0 5 ,2 4,89 % 0 5 ,2 % 0 7 ,1 05,11 Bestand Schacht 02 a r g r e n iz u p a K Bestand Schacht 07 % 0 5 ,1 % 0 0 ,2 Bestand Schacht 06 3,67 7 6 ,3 % 0 0 ,2 % 0 0 ,2 Bestand Schacht 05 Bestand Telekomschacht erhalten Bestand Schacht 05 7 ,4

0 4 0.0 9 m 0 0 0 0 + 4 2 0 1 1 8 . 1 5 . = 2 8 m = 0 6 0 1 R + 1 8 R = . 1 2 6 H 1= H , 0 5 7 0 ,7 7 .0 6 9 8 5 0 0 1 . . + 1 6 8 . 1 0 0 8 + 9 0 1 m 0 3 + P 2 8 T + . 1 2 6 1= 1 H E ,6 0 A 7 0 .5 7 4 0 + 1 .7 % 0 9 ,1 7 % 0 2 ,2 % 0 4 ,0 0 + 1 A 2 1 = R A 15 8 .3 7 0 + 1 ∞ = R 0 0 .0 7 0 + 1 0 0 .5 6 0 + 1 5 7 ,4

0 0 .0 6 0 + 1 Bestand Schacht 03 m 3 8 9 .2 6 1= H ,4 0 2 .5 5 0 + 1 E A 0 0 .5 5 0 + 1 3 0 2 .7 .0 1 2 8 6 % m 0 0 .0 5 0 + 1 2 2 . 5 8 . 0 0 0 0 0 % m 0 0 .5 4 0 + 1 m 6 6 1.3 6 1= H ,5 9 7 .4 4 0 + 1 A A pp oo dd ee ss tt 0 0 .0 4 0 + 1 % 0 0 ,1 % 0 7 ,1 % 0 9 ,1 ppooddeesstt 0 0 .5 3 0 + 1 4 -Q

1 5 9 1

0 0 .0 3 0 + 1 m 4 9 5 .3 6 1= H ,0 0 5 .9 2 0 + 1 E A 2 2 . 5 8 . 0 0 0 0 0 % m 0 0 .5 2 0 + 1 4 2 . 4 60 .9 0 9 9 % m m 7 2 9 .3 6 1= H ,0 0 5 .0 2 0 + 1 A A 4 0 0 .0 2 0 + 1 6 2 . 4 60 .9 0 9 9 % m 0 0 .5 10 + 1 2 1 . 2 0 8 . 3 2 7 7 1 % m % 0 8 ,0 % 0 5 ,0 m 9 3 3 .4 6 1= H ,3 3 5 .110 + 1 E A 0 0 .0 10 + 1 0 0 .5 0 0 + 1 0 A + A 98 9 0 . + 9 9 0 8 4 8.4 0 0 .0 0 0 + 1 6 e R R 8 ∞ i = R n , g 19 2 .9 9 9 + 0 = = a H n 6 = R g 1 = 6 ∞ 1 8 6 0 5.1 0 N

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B ta

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ch k

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1 hacht erhalten

km = 1+050.000 km = 1+025.000 km = 1+000.000 1 9 7 0 m07 0 8 0 2 . m 1 2 0 = 6 0 = 2 ∞ 1 8 2 R = . R 2 H

= 6 2 1 , = 3 R R 6 H 6 4 0 . , 6 8 0 0 0 2 0 1 . 4 . 0 2 0 2 0 . 4 5 . 2 + 2 5 3 1 0 . 1 2 5 2 1 2 2 1 = 1 + + . R + 2 2 4 1 1 1 + + 2 1 0 1 P 2 0 5 . . 7 0 P 1 + H 1 2 = T + 1 R 3 1 4 2 .9 0 2 + 1 0 0 .5 0 2 + 1 5 .7 1 = R 8 5 0 .3 0 2 + 1 ∞ = R % 0 7 ,2 0 0 .0 0 2 + 1 % 0 2 ,2 22 -Q 0 0 .5 9 1+ 1 0. 5 6 7 % 0. 6 9 4 % 1 2. 3 4 2 m 7. 2 0 4 m 0 0 .0 9 1+ 1 k m = 1 + 2 2 2. 6 4 6 h T S = 1 6 2. 8 7 0 m H = 0 m T = 0. 0 0 0 m f = 0. 0 0 0 m 0 0 .5 8 1+ 1 2 0 3 .0 .0 0 7 0 1 k % m

m 0 0 .0 8 1+ 1

= 1 1+ 8 1 4

7 0 5

9 4 . . . 2 0

9 0 0

8 0 0 3 8 % m 0 0 .5 7 1+ 1 0 5 0 0 .0 7 1+ 1 . . 2 0 0 0 0 0

k % m

m 6

= 1+17 2 0

4 6 .4 0 0 .5 6 1+ 1

. .

9 5 1

8 4 8

7 1 % m 0 0 .0 6 1+ 1 8 0 0 .5 5 1+ 1 2 0 6 .4 .5 14 8 0 0 .0 5 1+ 1 1

k % m

m = 1+14 4 0

8 1 4 .0

. .

4 5 0 0

0 9 0

6 6 % 0 0 .5 4 1+ 1 m 0 0 .0 4 1+ 1 0 0 .5 3 1+ 1 12 0 0 .0 3 1+ 1 0 0 .5 2 1+ 1 % 0 0 ,2 0 0 .0 2 1+ 1 3 -Q 0 0 .5 11+ 1 0 0 .0 11+ 1 14 4 0 4 .0 . trh a fn iE 5 0 9 0 6

k % 0 0 .5 0 1+ 1

m m ∞ = R 118 .3 0 1+ 1

= 1 0 1 = R

+10 2 1

3 1 . .

. 1 7

8 0 8

1 2

0 5 % m 0 0 .0 0 1+ 1 00.590+1 6 1 1.10 2 2 1. 7 % 85 m k 0 m h .7 T 1 3 = S 8 2 . 1 % 0 = H + 2 0 6 1 = T 8 6 2 2 m 5 = . . f 0 7 0 2 9 0 4 = 5 0 . 5 m 0 5 m . 0 0 2 m 1 m hTS H T f = = = = 1 5 5 0 6 0 . . 2 0 3 0 0 2 . 0 5 7 m 2 0 m m m hTS H T f = = = = 1 5 4 0 6 0 . . 0 5 3 0 2 0 . 7 0 0 m 2 0 m m m hTS H T f = = = = 1 9 1 0 6 1 0 . . 0 4 5 0 7 . 3 8 4 m 3 7 0 m m m h T S = 16 5 .12 0 m k m = 0 + 9 8 7 .7 2 9 12 .2 7 1 m 2 .0 3 7 % 0+978.097 R = ∞ B or n g a s s e 12

8 hTS = 162.910 m hTS = 162.920 m hTS = 163.030 m hTS = 163.030 m

H ∞ = R 00.03

7 2

8 +

9 1 .432+1 1 0 2 .7 .3 2 8 7 3 h k T % m m S H T f = = = = = 1 1 0 0 0 + 6 . . 0 0 2 2 m 0 0 0 . 2 0 9 0 0 3 3 .

1 0 . 0 . 0 m m 0 0 5 7 0 m 8 1 % m % 7 6 5 .0 m 2 4 3 .2 1 2 3 4. 9 8 7 1

2. 8 0 0 m

6 1

0. 6 9 4 7 % . 2 0 4 m 0. 7 2 7 % 1 2 k . m 3 8 3 h = T m 1 S + 2 = 1 5 1 H . 6 4 2 4 = . 8 2 0 T 2 0 m = m 0 f . 0 = 0 0 0 . m 0 0 0 m H T f = = = 0 0 0 . . 0 0 m 0 0 0 0 m m H T f = = = 0 0 0 . . 0 0 m 0 0 0 0 m m H T f = = = 0 0 0 . . 0 0 m 0 0 0 0 m m H T f = = = 0 0 0 . . 0 0 m 0 0 0 0 m m

+6 1 1

== mS 4 k h T 4 8 1 8

3 9

7 1 1

H gwd.052_nalpegaL_nehcaA_ztalpretaehT_5PL_327062\gnunalpsgnurhüfsuA

• 5PL\enälpegaL_70\DAC\negalretnunalP-50\essinbegresgnunalP-30\nehcaA ztalpretaehT 5101\49L bulC-403:P

Legende

Scheinfuge (SF)

Pressfuge (PF)

Raumfuge (RF)

Schwerlast Kastenrinne

Schlitzrinne

Straßenablauf

Kanalschacht

Hinweis:

Die tatsächliche Fungenlage und benötigte Bewährung wird vor

Baubeginn von der Ausführenden Fachfirma für Betonbau festgelegt.

Dieser Plan gilt lediglich als Konzept der Plattenaufteilung! N

Hinweis: Anpassungen der Pläne vor dem Ausführungsbeginn bleiben vorbehalten.

Fachbereich Mobilität und Verkehr Der Oberbürgermeister

Abteilung 68/500 Theaterplatz Aachen gez.

1. BA + 2. BA Theaterstraße und Theaterplatz

Leistungsphase 5

Fugenplan Betonfahrbahn

Dr. Silke Roder

Plan Nr: Planerin Zeichnerin M. = 1:250

5 m Juli 2026

2020_027_AP_L6 MJE RTH

ETRS 89 UTM, HST 160